$\left(x+4\right)\left(x-8\right)$
$x+1\geq 3-2x$
$\frac{63a^2}{7a^5b}$
$\left(y\right)dy\:=\:-\frac{\left(1+y^2\right)dx}{x}$
$-6^{x-1}+3b^{y-2}+4a^{x+1}-7b^{y-2}$
$2\sin x+3=2$
$4x^2-22x+10$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!