$\int tan\left(2x\right)\sqrt{sec\left(2x\right)}dx$
$\frac{\left(-160\right)}{-40}$
$\int\left(-6x-1\right)^{-3}dx$
$\frac{dy}{dx}=\frac{\left(x\:-\:xy\right)}{3}$
$b.\:\:-28\:+\:-34\:+\:\left[\left(-42\:+\:28\right)\:-\:18\right]$
$15m^3-30m^2+25m$
$\lim_{x\to0}\left(\frac{6x^2}{3x}\right)$
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