$\left(-4b^2a\right)^3$
$10\:sin\left(3x\right)=5$
$-\frac{2}{3}x-1\le2$
$\left(\frac{1}{6}x^3-\frac{2}{3}xy^2\right)^2$
$\lim_{x\to3}\:x^3+5x^2+4x-1$
$2\tan-\sec^2$
$6x-2<8+x$
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