$\sin\left(4x\right)+\sin\left(2x\right)$
$-7-47\cdot12-\left(-7\right)$
$\left(q^2-8\right)\left(q^2+3\right)$
$\left(t-10\right)^2$
$3x-7<5x+12$
$4-7-2$
$\frac{85}{161}-2.3193$
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