$\frac{1}{2}\left(0\right)+3$
$\int\left(3x^3+6\right)^4\left(9x^2\right)dx$
$\left(y^3-2x\right)^2$
$6x^2+43x-40$
$7y-8\cdot7y-8$
$5^{4x-x^2}=125$
$-x^2-10x-22\ge0$
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