$x+5y=8$
$\frac{27x^6+125y^3}{3x^2+5y^2}$
$\frac{3x^4-2x^3-10x^2-2x-6}{x+1}$
$\left(x+4\right)\left(x+4\right)\left(2x-4\right)$
$98x\left(-16\right)$
$4^{4x-5}=8^{3x-4}$
$\left(\frac{6}{5}x^{2}-\frac{1}{4}y^{2}\right)\left(\frac{6}{5}x^{2}+\frac{1}{3}y^{2}\right)$
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