$\frac{\left(x^3-1\right)}{x^3-3x^2+2x}$
$sin\:2x\:-\:sin\:x\:=\:0$
$\frac{d^2}{dx^2}\left(e^{3x}\cdot cos2x\right)$
$x^4-xy^3-xy^3+y^4$
$g+8>6$
$7x-28=42$
$\left(\frac{\sin\left(x\right)}{\cos\left(x\right)}+\cos\left(x\right)-1\right)$
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