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Find the limit of $\frac{x^2+1\cdot -8x+7}{x^3+1\cdot -3x+2}$ as $x$ approaches $3$

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 Solution

 Formulas

 Videos

Calculus - Evaluating a limit by factoring, lim(x tends to -1) (x^2 + 4x + 3)/(x + 1)

https://www.youtube.com/watch?v=klQ7xZ0PU5U

Tutorial - Condensing logarithmic expressions ex 12, 1/3(2ln(x+3)+lnx-ln(x^2-1))

https://www.youtube.com/watch?v=l8AE8UzknbY

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Calculus - Learn how to evaluate a limit by factoring, lim(x tends to -1) (x^2 - 5x - 6)/(x + 1)

https://www.youtube.com/watch?v=-nTo1qgNDLE

Tutorial - How do we solve a system of linear equations using any method (x+3)/4+(y-1)/3 =1, 2x-y=12

https://www.youtube.com/watch?v=spCN2XloBBQ

Limits by direct substitution | Limits and continuity | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=cfOcOgr0E7U

 Function Plot

Plotting: $\frac{x^2+1\cdot -8x+7}{x^3+1\cdot -3x+2}$

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Answer Assistant

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Got a different answer? Verify it!

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Limits by Direct Substitution

Find limits of functions at a specific point by directly plugging the value into the function.

 Used Formulas

See formulas (1)

 Related Topics