$\lim_{x\to3}\left(\frac{x^2-6x+9}{x^4-81}\right)$
$\left(3x-3\right)\left(3x-2\right)$
$\left(2ax+3xy^3\right)$
$6x^2-8x=12$
$\frac{10\left(-60\right)}{6}$
$x^2+12x-12$
$-3\left(x\:-6\right)\:+\:9\left(-2\:x\:-5\right)$
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