$+9m+5m+10m+2m$
$\int te^{-5t}dt$
$\frac{r}{6}+3=1$
$2x\frac{dy}{dx}+4y=3$
$2a+3b+5^2$
$=\frac{\left(2x-6\right)^4}{\left(3x+2\right)^2}$
$\lim_{x\to\infty}\:\left(\frac{1}{2}\right)^x+\left(-2\right)^x$
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