$\log_b\left(9\right)$
$\left(3a^3-4b^5\:\right)^3$
$\int\frac{1}{\left(x^2+1\right)\left(3x^2+x^3\right)}dx$
$8m^5n+40m^3-16mn$
$\frac{2}{10x+3}\frac{dy}{dx}=2y$
$3x^2+2xy^3+y;\:x=1;\:y=2$
$1,\frac{-3}{3}$
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