$\left(3y+5\right)\left(2y+4\right)$
$12x^2-31<2$
$\left(x^2+3\right)\left(x^3+x^2+3x+3\right)$
$-35-\left(-1.28\right)$
$10b-3ab^2$
$\frac{4x^3-6x^2+8x+1}{2x-4}$
$\lim_{x\to\infty}\left(\left(\frac{1}{2}\right)^x\right)dx$
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