$x-6\le3x+12$
$16x^2+80x+100$
$20+90+512\:$
$x^2+y^2=b^2$
$\lim_{x\to\infty}\left(\frac{8y^3-3y+5}{4y^3-5y+2}\right)$
$-7-3b-5b+4$
$\frac{2x^3}{3+4x^2}$
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