$\frac{-7x^4+8x^3+5x^2+4x+2}{6+x^2+3x}$
$y=\:\frac{-5}{\sqrt{x^2}}$
$\lim_{n\to\infty}\left(\frac{ln\left(n+4\right)}{\sqrt[6]{n}}\right)$
$12x\:-5\left(x\:+\:6\right)\:-\:3$
$\left(x^2-x+3\right)\left(3y^2+6y+1\right)$
$a^2-149+49$
$4x^2-16x\cdot16$
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