$\left(w^2+2\right)\left(w^2+3\right)$
$\frac{dy}{dx}\left(x^3+ax^2+bxy^2+y^3\right)$
$\frac{x^2-4}{x+4}$
$2p^2\:x\:2p^2$
$\sqrt[3]{8x^{12}y^6z^3}$
$-2y^2\left(x-y\right)$
$y+xy^2-x\frac{dy}{dx}=0$
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