$5\sin^2\left(x\right)+\sin\left(2x\right)-5$
$141-41-\left(-19\right)$
$4\tan\left(x\right)^2+7\tan\left(x\right)-4=0$
$9x\left(4x-5x+3\right)-6x$
$\sqrt{x}\left(x-1\right)$
$\left(-3x+6\right)\left(-3x+7\right)$
$\frac{16m^8-100}{4m^4-10}$
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