$\lim_{x\to0}\left(\frac{x+6}{x}\right)$
$\left(\frac{7}{3}\right)\cdot\left(-10x\right)$
$\frac{dy}{dx}\:x^2=y\left(y+3\right)$
$\frac{a^4+a}{a+1}$
$3\log6\left(12\right)-\log6\left(48\right)$
$\int m\:tdx$
$\left(\frac{2}{3}\right)^{-2\cdot2}$
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