$27+395$
$\frac{25a^4}{36}+\frac{1}{25}-\frac{a^2}{3}$
$2x<6$
$-1-\left(\frac{2+3}{5}\right)-\left(\frac{2^2+3^2}{5^2}\right)-\left(\frac{2^3+3^3}{5^3}\right)-\infty$
$3\left(g+4\right)$
$\frac{d}{dx}2y^3+4x^2-y=x^6$
$107\cdot93\:\:\:\:\:\:\:\:\:\:$
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