$2x+3<\:9-x$
$\left(7x=11\right)^2$
$4x+8\le0$
$\left(\frac{4}{x}\right)-3>\left(\frac{2}{x}\right)-7$
$\lim_{x\to\infty}\left(-x-5\right)$
$\left(\frac{2}{b}+1\right)^2$
$\sqrt{27a}$
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