$5x\left(x-3\right)-4x^2\ge x\left(x+1\right)+112$
$\left(\sqrt[3]{a^6.b^9}\right)^2$
$5x<5x+4$
$\lim_{x\to1}\left(\frac{x^5-1}{x^8-1}\right)$
$-18m^2+27m\cdot n$
$\frac{52sin45}{sin59}$
$-5\cdot2-16$
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