$145-\left|-28\right|$
$3x+4<13x+12$
$y=\frac{\left(sin\left(x\right)\right)^2\left(tan\left(x\right)\right)^4}{\left(x^2+2\right)^2}$
$5a\left(3b^2+6c^5-d^2\right)$
$4^3\cdot4^{-4}\cdot4^2$
$-2\cdot4+3$
$\sqrt{4}+\:\sqrt{25}-\sqrt{49}$
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