$\int\frac{\left(3x^3+6x^2+7x-1\right)}{x^3}dx$
$18-15-12-36+95-5+18$
$-39\:+1\:\left(-44\right)$
$\sin^2\left(x\right)-1=2cos^2\left(x\right)$
$\left(x^2+4\right)\frac{dy}{dx}=\left(xy\right)$
$\int\frac{2x^2-x+8}{\left(x^2+4\right)^2}dx$
$\left(2x^2+y\right)\left(2x-y\right)$
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