$\left(4\left(2.99\right)-13\right)^{2.99}$
$0.8\:x\:0.15\:=\:\:\:$
$\left(4x-12\right)\left(x+1\right)$
$\left(\frac{3x^2}{2}+2x\right).\:\left(\frac{3x^2}{y}-2x\right)$
$\frac{dy}{dx}=10x^{\frac{4}{5}}$
$tg\:a+ctg\:a=\frac{1}{sen\:a\:cos\:a}$
$\frac{x^2}{x+2}-4$
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