$cos3x=\frac{\sqrt{3}}{2}$
$18x^3-12x^2+8x$
$\frac{dy}{dx}=\left(x+2\right)\left(3-y\right)$
$7^3\cdot7^3$
$\lim_{x\to2}\left(\frac{x^2-6x+10}{x-1}\right)$
$\int\frac{1}{13y}dy$
$\frac{d^7}{d^3}$
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