$t+\frac{-5}{t}-1$
$16\sin^2x=8$
$\left(\frac{\left(-2\right)}{\frac{x+\left(3x^2\right)}{4}}\right)^7$
$-4x^2-12x+4$
$\int\cos\left(3x\right)^4\sin\left(3x\right)dx$
$\lim_{x\to0}\left(\frac{sin5x+xcos2x}{x^2+x}\right)$
$\frac{\left(-8\right)^8}{\left(-8\right)^8}$
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