$\int_0^1\left(\frac{1}{\left(1-x\right)^2}\right)dx$
$-8\left(-2+3\cdot2\right)$
$\int\frac{x^3+1}{x-2}dx$
$\lim_{x\to\infty}\left(x-xe^{\frac{1}{x}}\right)$
$\frac{x^4-x+1}{x+2}$
$3v+5-9v+2$
$\frac{dy}{dx}=\left(e^x+5\right)^2$
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