$sin\left(\frac{\pi}{2}+\frac{3}{5}\right)$
$-x-5>-2x-6$
$-\frac{1}{2}\left(16-8x\right)$
$\frac{4x^2-3}{x-5}$
$\left(x\:-\:3\right)^2+\:\left(x\:-\:1\right)\left(x\:+\:7\right)\:-\:2$
$4-0.75$
$3x-4\ge16$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!