$9-\left(6+25\right)$
$\frac{x+7}{x-2}\le2$
$y^'-3xy=y^2x$
$-16v^2+72>25$
$\frac{-6x-5}{9}\le5$
$\int\frac{9}{x^2-5x+6}dx$
$y\frac{dy}{dt}=t\left(1+y^2\right)$
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