$\frac{cos2x}{cos^2x}=1-tan^2x$
$3x^{2}+6x=5$
$\left(p-\frac{a}{v^2}+\frac{2ab}{v^3}\right)^2$
$x2+5x-25=0$
$\lim_{x\to\infty}\left(1+tan\left(x\right)^{x^2}\right)$
$119x+14$
$\left(+3\right)+\left(-2\right)-\left(+4\right)+\left(-3\right)\left(-5\right)+2$
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