$\frac{x-4x+3}{x-1}$
$\int\:\frac{\left(x^2+x-10\right)}{\left(2x-3\right)\left(x^2+4\right)}dx$
$\int\left(5x+1\right)e^xdx$
$0.8\cdot0.2$
$\left(3x+2\right)\left(2x-5\right)$
$x^2-16x+3$
$9m^2+12m+4m^2$
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