$-2h^2+15h+8$
$\lim_{x\to\infty}\left(\frac{42x\cos\left(x\right)-42\sin\left(x\right)}{x\sin^2\left(x\right)}\right)$
$\left(4cm\right)^2\cdot4$
$45t^5-14t^5$
$64\cdot22$
$\left(3w+2z\right)^2$
$24x\cdot x$
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