$57\cdot10^4$
$\frac{6x}{9x^2}$
$\left(x^2\:+1\right)^3$
$x^2-x+5$
$-4m\:-\:6m$
$\left(y^2-6xy\right)-\left(7x^2\right)y'=0$
$\left(x+3\right)\left(x+4\right)=\left(x+3\right)\left(4+x\right)$
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