$\int\frac{x-1}{x^2\left(x^2+1\right)}dx$
$\left(-\:4c\:-\:5d\right)^2$
$\frac{2}{1+sinx}=\left(sec\left(x\right)-tan\left(x\right)\right)^2+1$
$x^2+10x+39=23$
$\frac{d}{dx}\:\frac{x^2}{16}\:+\:\frac{y^2}{25}\:=\:1$
$\sqrt{12a}^2$
$\frac{846}{9}$
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