$\int\cos\left(\frac{1}{4}x\right)dx$
$\frac{1}{1+\tan^2x}+\frac{1}{1+\cos^2x}=1$
$x^2-8x+9=0$
$\sqrt[2]{-1}$
$\int\left(\frac{2}{5x+1}\right)dx$
$\lim_{z\to\infty}\left(\frac{z^2+1}{z-1}\right)$
$\frac{dy}{dx}=\frac{1+x}{2-y}$
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