$4\left(2c-1\right)+6=14+6\left(3c-2\right)$
$\left(-45\right)\left(-80\right)$
$\left(\frac{4}{5}b^3-\frac{7}{2}c^4\right)\:\left(\frac{4}{5}b^3+\frac{7}{2}c^4\right)$
$3x=3$
$\int\frac{2x-5}{\sqrt{3x-x^2}}dx$
$9h^2-30b^2h+25b^4$
$64n^3-125m^6$
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