$\left(2x^213\right)^5$
$\lim_{x\to\infty}1.03^x$
$\left(11\right)\left(-0.25\right)\left(-2\:\frac{3}{5}\right)$
$\left(7a^2b^2+5x^2\right)^2$
$6a^2+8a+2$
$\frac{-28+28}{-16-4-12}$
$4sin\left(x\right)^2+4cos\left(x\right)-8sin\left(x\right)cos\left(x\right)-4$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!