$\left(8m\:-\:3b\right)^2\:=\:$
$\left(3c\right)^5$
$\int x\left(x^2-7\right)dx$
$\int\frac{x^3-5x}{x^2+4x+3}dx$
$\frac{3v}{8v^2}$
$2x-y-3=\frac{y\left(r-1\right)}{\left(r-2\right)}$
$8\left(h-1\right)=6h+4+2h$
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