$p^4-p^2-p+1$
$\frac{6}{4-x}\:,\:c=1$
$\lim_{x\to2}\left(\frac{2x}{\left(x-2\right)^2}\right)$
$xy=6$
$7\left(a+b-c\right);\:a=5;\:b=-4;c=-1$
$-\frac{5}{9}x-\frac{1}{3}x$
$\left(4y^2-3x^2\right)^5$
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