$\lim_{x\to\infty}\left(4x-5x\right)$
$x^2-6x-7>0$
$\left(3m^3-2n^4\right)^2$
$\left(\frac{3}{2}m^{2}-4n^{3}\right)^{3}$
$\int\frac{9x-8}{\left(x-3\right)\left(2x-5\right)}\:dx$
$x^2+36\ge13x^2$
$\frac{\cos\left(a\right)-2\sin^2\left(a\right)\cos\left(a\right)}{\cos\left(a\right)}$
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