$3x^2-12x+1$
$-2x^21x+0=0$
$\frac{\left(3a\right)^4-\left(2b\right)^4}{3a-2b}$
$2-3x+7x-x+2x^2+7-5$
$-\frac{x}{4}=12$
$-\frac{8}{5}y-\frac{1}{10}y$
$\left(-2\right)-\left(-8\right)+\left(-5\right)-\left(-6\right)$
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