$\frac{tan^2a}{seca}=seca-cosa$
$x ^ { 3 } - 3 x + 2$
$\left(\frac{1}{3}+2b\right)^3$
$\int x\left(ax-b\right)^{alpha}dx$
$\int\frac{x^2+x}{\left(x-1\right)\left(x^2+1\right)^2}dx$
$1,728b^3+1,728y^3$
$\left(6z\:-\:3\right)^3$
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