$\left(\sqrt{6}\:+\:\sqrt{2^2}\right)\:+\:\left(\sqrt{6}\:-\:\sqrt{2^2}\right)$
$5\left(x+1\right)=4\left(x+2\right)$
$10^y+8=9$
$-67-56-78-98-65$
$\sqrt{196a^2}b^5$
$\frac{dx}{dy}=\sqrt{\left(x+y\right)}-1$
$\frac{2}{x}-\frac{1}{1}$
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