$3x\:+\:4\:\ge\:5$
$\int\cos\left(x\right)\frac{1}{\sin\left(x\right)^2}dx$
$6a\cdot6a$
$3x+8=4x+4$
$-3\int\left(\frac{1}{x}\right)dx$
$x=x'$
$\int_0^1\left(\cos\left(hx\right)-\sin\left(hx\right)\right)^2dx$
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