$\frac{1+b^2}{1+b}$
$sec^2x=sin^2x$
$\left(3a^4+6b^3\right)^3$
$\frac{10x^2-3x^3+11x+6}{x+2}$
$\frac{2}{4+4x}$
$\left(16y\right)^2\left(-49\right)$
$\left(2x+3\right)^2-\left(x+4\right)^2-3\left(x+1\right)^2$
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