$+0-1005$
$\left(a+h\right)^3$
$x^2-26x=-15$
$\lim_{x\to0}\left(\frac{\tan^5\left(2x\right)}{x.\sin^3\left(3x\right)}\right)$
$2\cdot2\cdot2\cdot2\cdot3\cdot5\cdot6$
$3\:+\:4d\:+\:2d$
$x^2-a-1\left(x+a\right)$
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