$\left(3p^2-4u\right)^2$
$\int\frac{x-2}{x\left(x^2-4x+5\right)^2}dx$
$-\left(-6+4\right)\left|2-5\left(4-3\right)+2\left(7-3\right)+2-1\right|$
$x^2-1-8x^4-3x^2+5x+4-5x^4+2x^2-4x$
$z^2-5z+6.25$
$\left(4x+3\right)+x$
$2\:\:cot\:x\:+\:1\:=\:0$
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