$x^2+x-240$
$\lim_{x\to0}\left(\frac{x^2+5x}{x}\right)$
$4x^2-2x+3$
$sin\left(\frac{2.4619}{2}\right)$
$\left(4v\:-\:\:6\right)^2$
$-4=x^2+4x$
$\left(x^3+8\right)\left(x^3-1\right)$
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