$5x\:and\:4xy$
$x^2-5x\ge\:-8$
$7+5x^2<5\left(4-x\right)^2$
$v+v+v$
$3\left(x-3\right)-3\left(2x-3\right)\le5-3x$
$\int\:\left(t-3\right)e^t\:dt$
$x^{2\:}+19x+12=\left(4x+3\right)\left(x+4\right)$
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