Compute the integral
$\int\frac{x}{\sqrt{x^2+9}}dx$
$\int\frac{dx}{x^2\sqrt{4-x^2}}$
$\int\frac{1}{\sqrt{x^2-36}}dx$
$\int\frac{1}{\sqrt{1-x^2}}dx$
$\int\frac{x}{\sqrt{16-x^2}}dx$
$\int\frac{1}{\sqrt{1-5x}}dx$
$\int\frac{x^3}{\sqrt{x^2+4}}dx$
Integrals of Rational Functions
9. See formulas
~ 0.29 s
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