$x^2-4x-3$
$\frac{7x^4-4x^3+4}{x^3}$
$\left(p^{10}q^{12}\:r^{10}\right)^{-1}$
$\frac{3x-5}{3-x}\le1$
$36y^2-9$
$\left(4x^2+5\right)^5$
$\left(\frac{a^5c^4d^3}{b^4}\right)\left(\frac{d^6}{c^9}\right)$
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